Code:'this gives run time error 13 type mismatch) Private Sub Label1_Click(Index As Integer) Dim Pressed As String If frmMenu.Label1(0) Then Pressed = "1" If frmMenu.Label1(1) Then Pressed = "2" If frmMenu.Label1(2) Then Pressed = "3" If frmMenu.Label1(3) Then Pressed = "4" Select Case Press Case "1" MsgBox "menu 1 pressed" Case "2" MsgBox "menu 2 pressed" Case "3" MsgBox "menu 3 pressed" Case "4" MsgBox "menu 4 pressed" End Select End Sub




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