Results 1 to 3 of 3

Thread: [RESOLVED] c# Hotel Check-In / Check-Out System using objects

Threaded View

  1. #1

    Thread Starter
    Fanatic Member Emcrank's Avatar
    Join Date
    Jan 2009
    Posts
    566

    Resolved [RESOLVED] c# Hotel Check-In / Check-Out System using objects

    EDIT: See Second Post

    Basically I am trying to create a program that allows someone to check in new guests to rooms that are available.
    This is what I have so far to create my guests and rooms and add the rooms to a list.
    I am wanting to know how I can loop through each room in the "AllRooms" List and check whether its property of booked is true or false and check the room type against a combobox which has the 5 types of room in and then display all the room numbers that are not booked and are of that room type in a list box on the right hand side - See screenshot of design. All help appreciated.

    Room Types are: Single Room, Double Room, Queen Suite, King Suite, Penthouse Suite
    Name:  capture.jpg
Views: 4874
Size:  17.6 KB

    RoomClass
    Code:
    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    using System.Threading.Tasks; 
    
    namespace Hotel_Check_In
    {
         public class Room
            {
             public static List<Room> AllRooms;
             public int RoomNumber { get { return this.RoomNumber; } set { this.RoomNumber = value; } }
             public string RoomType { get { return this.RoomType; } set { this.RoomType = value; } }
             public Boolean booked { get { return this.booked; } set { this.booked = value; } }
            
    
    
    
             public Room(int roomNumber)
             {
                 RoomNumber = roomNumber;  //adds room Number to room number property
             }
    
             public Room(int roomNumber, string roomType)
             {
                 RoomNumber = roomNumber;
                 RoomType = roomType;
             }
    
             public void AddRooms(int noOfRooms, string roomType)     //Add new Rooms (method for adding rooms to list on load)
             {
                 if (AllRooms.Count == 0)                       //check if any rooms exist already
                 {
                     for (int i = 1; i <= noOfRooms; i++)
                     {
                         Room newRoom = new Room(i);
                         AllRooms.Add(newRoom);
                         newRoom.RoomType = roomType;
                         newRoom.booked = false;
                     }
                 } else {
                     for (int i = AllRooms.Count + 1; i <= noOfRooms; i++)              //if rooms exist then +1 onto current room total so no room has the same number
                     {
                         Room newRoom = new Room(i);
                         AllRooms.Add(newRoom);
                         newRoom.RoomType = roomType;
                         newRoom.booked = false;
                     }
                 }
             }
    
            }
    }
    GuestClass
    Code:
    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    using System.Threading.Tasks;
    
    namespace Hotel_Check_In
    {
        public class Guest
        {
            public string Name {get {return this.Name;} set {this.Name = value;}}
            public int rNumber {get {return this.rNumber;} set {this.rNumber = value;}}
            public DateTime arrivalDateTime { get { return this.arrivalDateTime; } set { this.arrivalDateTime = value; } }
            public DateTime leavingDateTime { get { return this.leavingDateTime; } set { this.leavingDateTime = value; } }
            public static List<Guest> AllGuests;
          
        public Guest()
        { }
    
    
        public Guest(string name, Room allocatedRoom)
        {
            Name = name;
            rNumber = allocatedRoom.RoomNumber;
            
        }
    
    
            public static void CheckIn(string GuestName, Room room, DateTime checkinDateTime, DateTime LeavingDateTime)
           {
                 Guest newGuest = new Guest(GuestName, room);
                
                
           }
        }  
    }

Tags for this Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  



Click Here to Expand Forum to Full Width