[RESOLVED] Fatal error: Function name must be a string in

[tendemo]

Hi I am trying to figure out how some code works but unfortunately the original code was poorly formatted

$q = "select password from users where username = '$username'";

   $result = mysql_query($q,$conn);

   if(!$result(mysql_numrows($result) < 1)){  // Affected line

      return 1; //Indicates username failure

   } 

Would be glad to find out whats wrong and a possible work around.