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Thread: [RESOLVED] Circular segment height?

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    Resolved [RESOLVED] Circular segment height?

    So i have an assignment at school. the first part of the assignment is finding out how many litres of liquid are in a cylinder. I have the following variables:

    d = 50 cm (diameter of circle)
    L = 120 cm (length of cylinder)
    h = 10 cm (height of circular segment)

    The Figure to the left is sideview of the cylinder, and the figure to the right is front view.
    Name:  shape.jpg
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    first part is easy.
    Find out how much liquid is in the cylinder
    Code:
    A=r^2/2 * ((pi*v)/180 - sin(v))
    A=312,5*(1,854587-0,96)=279,5581 cm^2
    
    V_(cylinder) = 279,5581 cm^2 * 120 cm = 33546,97 cm^3
    V_(cylinder) = (33546,97 cm^3)/(1000 cm^3/L) = 33,54697 L
    now the second part is where i'm stuck at.
    i need to find the new height of the circular segment, if i add 50 L liquid. so our new V_(cylinder) is 50 + 33,54697 = 83,54697 L.

    how would i go about doing this? i can't exactly isolate V from the previous formula?
    Last edited by Justa Lol; Oct 29th, 2014 at 06:48 AM.

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