winhttp file upload, using data from html file upload form

[westconn1]

i posted this sample in vb6 earlier, but have decided it probably should, come into codebank

after several threads on automating file input elements in web page file upload forms,
after some searching here and on google, i have put together a simple example to upload files using winhttp, based on form in automated webbrowser or instance of IE

i only modified some code i found, all kudos to dulus http://www.access-programmers.co.uk/...d.php?t=155372
though i guess he got it from elsewhere anyway

the sample requires a form with file list (multi select) and command button
requires reference to winhttp
most of the code is in a small module

module

Function UploadXML(strformurl As String, strFileName As String, inputfile As String, Optional strUserName As String, Optional strPassword As String) As String
    Const HTTPREQUEST_SETCREDENTIALS_FOR_SERVER = 0
    Const HTTPREQUEST_SETCREDENTIALS_FOR_PROXY = 1
    
    Dim WinHttpReq As WinHttp.WinHttpRequest
    Dim strBody As String
    Dim strFile As String
    Dim aPostBody() As Byte
    
    Dim bound As String
    Dim boundSeparator As String
    Dim boundFooter As String
    
    bound = "AaB03x"
    boundSeparator = "--" & bound & vbCrLf
    boundFooter = "--" & bound & "--" & vbCrLf
    
    Set WinHttpReq = New WinHttpRequest

    WinHttpReq.Open "POST", strformurl, False
    
    If strUserName <> "" And strPassword <> "" Then
        WinHttpReq.SetCredentials strUserName, strPassword, HTTPREQUEST_SETCREDENTIALS_FOR_SERVER
    End If
    
    WinHttpReq.setRequestHeader "Content-Type", "multipart/form-data; boundary=" & bound
    strBody = boundSeparator

    strBody = strBody & "Content-Disposition: form-data; name=""" & "login" & """" & vbCrLf & vbCrLf & strUserName
    strBody = strBody & vbCrLf & boundSeparator

    strBody = strBody & "Content-Disposition: form-data; name=""" & "pass" & """" & vbCrLf & vbCrLf & strPassword
    strBody = strBody & vbCrLf & boundSeparator
    
    strFile = getFile(strFileName)
    strFileName = Right(strFileName, Len(strFileName) - InStrRev(strFileName, "\"))
'    strBody = strBody & "Content-Disposition: form-data; name=""" & "userfile" & """; filename=""" & strFileName & """" & vbCrLf & _

    strBody = strBody & "Content-Disposition: form-data; name=""" & inputfile & """; filename=""" & strFileName & """" & vbCrLf & _
        "Content-Type: text/xml" & vbCrLf & vbCrLf & strFile & vbCrLf

    strBody = strBody & boundFooter
    
    'convert to byte array
    aPostBody = StrConv(strBody, vbFromUnicode)

    WinHttpReq.send aPostBody
'    WinHttpReq.send strBody
    
    Do Until WinHttpReq.Status = 200
        DoEvents
    Loop
    
    UploadXML = WinHttpReq.responseText
    Set WinHttpReq = Nothing
End Function

Function getFile(strFileName As String) As String
    Dim strFile As String
    Dim nFile
    
    ' Grap the file
    nFile = FreeFile
    Open strFileName For Binary As #nFile
    strFile = String(LOF(nFile), " ")
    Get #nFile, , strFile
    Close #nFile
    
    getFile = strFile
End Function

part of code in command1

Set frm = wb.document.Forms(0)
For Each ele In frm.getelementsbytagname("input")
    If ele.Type = "file" Then fileinput = ele.Name
Next
formurl = frm.Action
For i = 0 To File1.ListCount - 1
    If File1.Selected(i) Then res = UploadXML(formurl, File1.Path & "\" & File1.List(i), fileinput)
Next

all variables need to be dimensioned of appropriate types to be passed to functions

where wb is a webbrowser, instance of IE or shell window, that has already navigated to the file upload form document

the web document form /php script used for this test was of the simplest design and did not require any additional inputs to be posted with the file
if other hidden or user inputs need to be posted to the php script, both the name of the input and the value of the input must also be included with the post data, by passing them to the function and adding them to data, it may then be better to use a param array to pass the parameters to the function

everything depends on the requirements of the php script /server

i have successfully tested the code to upload files to my webserver