hi all
i have a web page im working on, my first php page ever and im stuck with pictures
i want to add a picture to ever row of my search on the db
the picture is store under the localhost server but i cant get it to work. example below


PHP Code:
<img border=0img src="//localhost/vidpics/videotitle.jpg" width=40 height=40> 
on the image bit i need tobe able to use localhost not servers name and the image title(videotitle) needs to be able to change to each row.

PHP Code:
<?php
/* Change next two lines */
$db="vdidb";
$link = mysql_connect('localhost: 3306', 'user', 'password');
if (! $link)
die(mysql_error());
mysql_select_db($db , $link)
or die("Couldn't open $db: ".mysql_error());
 // $result = mysql_query( "SELECT vidnumber, videotitle, age, Runningtime, starring, hd, trilogy  FROM videolist")
$id = "%".$_GET["search"]."%"; 

// $result = mysql_query( "SELECT vidnumber, videotitle, age, Runningtime, werestoredFolder FROM videolist WHERE videotitle LIKE '".mysql_real_escape_string($id)."'")

$result = mysql_query( "SELECT vidnumber, videotitle, age, Runningtime FROM videolist WHERE vidnumber LIKE '".mysql_real_escape_string($id)."'")


or die("SELECT Error: ".mysql_error());
$num_rows = mysql_num_rows($result);
// print "There are $num_rows records.<P>";
print "<table width=200 border=1>\n";
while ($get_info = mysql_fetch_row($result)){ 
print "<tr>\n";
foreach ($get_info as $field) 
print "\t<td>$field</td>\n";

print "</tr>\n";
}
print "</table>\n";

print "There are $num_rows records.<P>";
mysql_close($link);
?>
<br>

<body>