[RESOLVED] XML Deserialization (Hydration)

[Zeelia]

Hi!
I'm having a problem that's driving me crazy; I can't understand how to convert the XML structure into a class structure (that I want to use to hydrate a XML document).

The XML document looks like this:

<?xml version="1.0" encoding="utf-8"?>
<artists xmlns:opensearch="http://a9.com/-/spec/opensearch/1.1/" xmlns="http://www.spotify.com/ns/music/1">
  <opensearch:Query role="request" startPage="1" searchTerms="Piano Tribute Players"/>
  <opensearch:totalResults>2</opensearch:totalResults>
  <opensearch:startIndex>0</opensearch:startIndex>
  <opensearch:itemsPerPage>100</opensearch:itemsPerPage>
  <artist href="spotify:artist:4Xx6QMLTWppMwdABkN0Afj">
    <name>Piano Tribute Players</name>
 
    <popularity>0.73531</popularity>
  </artist>
  <artist href="spotify:artist:4oG2lcwDOqbB74BOE4O7o7">
    <name>Piano Players Tribute</name>
    <popularity>0.50211</popularity>
  </artist>
</artists>

And I need to get all that information into a class but I'm really lost.
To begin with, I don't know how to create the sub-node (artist) in a class, I've tried with Public Structure and Public Property but I think that it needs to be another class, am I right?

Here's what I currently have:

<Serializable(), XmlRoot()> _
Public Class artists
    Public totalResults As Integer
    Public startIndex As Integer
    Public itemsPerPage As Integer
    Public Class artist
        Public name As String
        Public popularity As Double
    End Class
End Class

Another thought that I have is that the artist node isn't only one, so how would I do to create multiple artist classes....

Please help me!
//Zeelia