Hi,
I want to submit game scores to different MySql tables (tab1-tab2) according to the type of the game (1-4).
The PHP code reads the score, some more data and the type of game, stored in $gametype. then it goes through elseif statements to choose the right table.
However, something is not working in this code.
Can someone see a syntax error that I'm not able to see?
Thanks!

PHP Code:
<?

$username="******";
$password="******";
$database="******";
$gametype=0

    // Connect to database
    mysql_connect ("***********.com" , $username, $password)  or die( "cannot connect" );
    mysql_select_db($database) or die ("cannot open" );

//if(isset($_GET['name'], $_GET['score']))
if(isset($_GET['name'], $_GET['city'], $_GET['country'], $_GET['score'], $_GET['date'], $_GET['gametype']))
{

$name = mysql_real_escape_string($_GET['name']);
$city = mysql_real_escape_string($_GET['city']);
$country = mysql_real_escape_string($_GET['country']);
$score = (int) $_GET['score'];
$date = mysql_real_escape_string($_GET['date']);
$gametype = (int) $_GET['gametype']);
 print ($gametype);

if ($gametype == 1) {
$result = mysql_query ("INSERT INTO tab1 (Name,City,Country,Score,Date) VALUES ('$name','$city','$country','$score','$date')");
} elseif ($gametype == 2) {
$result = mysql_query ("INSERT INTO tab2 (Name,City,Country,Score,Date) VALUES ('$name','$city','$country','$score','$date')");
} elseif ($gametype == 3) {
$result = mysql_query ("INSERT INTO tab3 (Name,City,Country,Score,Date) VALUES ('$name','$city','$country','$score','$date')");
} elseif ($gametype == 4) {
$result = mysql_query ("INSERT INTO tab4 (Name,City,Country,Score,Date) VALUES ('$name','$city','$country','$score','$date')");

}

if($result)
    echo 'score submitted!';
    
mysql_close();

?>