I have a form that contains a PicutreBox called picTray. I then have this code:
It works yet it doesn't...Everything works fine except when I double click which would call this code:Code:Private Type NOTIFYICONDATA cbSize As Long hwnd As Long uID As Long uFlags As Long uCallbackMessage As Long hIcon As Long szTip As String * 64 End Type Private Declare Function Shell_NotifyIcon Lib "shell32.dll" Alias "Shell_NotifyIconA" (ByVal dwMessage As Long, lpData As NOTIFYICONDATA) As Long Private Const NIF_ICON = &H2 Private Const NIF_MESSAGE = &H1 Private Const NIF_TIP = &H4 Private Const NIM_ADD = &H0 Private Const NIM_DELETE = &H2 Private Const NIM_MODIFY = &H1 Private Const WM_MOUSEMOVE = &H200 Private Const WM_LBUTTONDBLCLK = &H203 Private Const WM_LBUTTONDOWN = &H201 Private Const WM_RBUTTONDOWN = &H204 Private tTrayIcon As NOTIFYICONDATA Private Sub Form_Load() 'Create a Tray Icon picTray.Visible = False With tTrayIcon .hIcon = Icon .hwnd = picTray.hwnd .szTip = "Test" & Chr(0) .uCallbackMessage = WM_MOUSEMOVE .uFlags = NIF_ICON Or NIF_MESSAGE Or NIF_TIP .uID = 1 .cbSize = Len(tTrayIcon) End With End Sub Private Sub Form_Resize() If WindowState = vbMinimized Then Hide 'Send it to the tray Shell_NotifyIcon NIM_ADD, tTrayIcon End If End Sub Private Sub Form_Unload(Cancel As Integer) 'Remove the Tray Icon Shell_NotifyIcon NIM_DELETE, tTrayIcon End Sub Private Sub picTray_MouseMove(Button As Integer, Shift As Integer, X As Single, Y As Single) Select Case ScaleX(X, vbTwips, vbPixels) Case WM_RBUTTONDOWN Case WM_LBUTTONDBLCLK Me.Show Me.WindowState = vbNormal End Select End Sub
I have to double click and then double click again to make the form show itself. Anyone know what's up?? Thanks in advance.Code:Private Sub picTray_MouseMove(Button As Integer, Shift As Integer, X As Single, Y As Single) Select Case ScaleX(X, vbTwips, vbPixels) Case WM_RBUTTONDOWN Case WM_LBUTTONDBLCLK Me.Show Me.WindowState = vbNormal End Select End Sub
Edited by _eclipsed_ on 03-10-2000 at 12:19 AM




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