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Sep 19th, 2008, 07:49 PM
#1
Thread Starter
Member
Maclaurin Series
HI Guys,
Just a quick questoin.
I have worked out a series expansion of
ln(x+1)/ln(x-1) which equals 2x+2/3x^3+2/5x^5........
I have been asked to find the series expansion for 1/2 ln(x+1)/ln(x-1)
Do I multiply my result with the scaler 1/2 or do I work out the Taylor again using
1/2 ln(x+1) devide 1/2ln(x-1)
as the functions instead
regards
Brendan
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