Using LHopital's Rule, I am to calculate;
(a) (ln(x))/x with limitation of x to infinity
(b) x*ln(x) with limitation of x to 0+

for (a) I did the normal differentiation which gives a 1/x if I'm not wrong. 1/x is a horrible answer to deal with coz in this case, it becomes 1/infinity. Anyone who can clarify?

for (b) I obtained (1+ln(x)) with limit of x to positive. replacing x by positive, I get an incredibly large answer. :Sick