[RESOLVED] Cubic Polynomials

[Sean12345]

From reading the other threads this question appears simple.

Is there any other way to factorise a cubic polynomial than by using the factor theorem?

I ask this because the factor theorem can be quite a tedious method if the number isn't an integer. For example if the cubic polynomial i am trying to solve is P(x) = x³+x²-4x-4 then it wouldn't take long to figure out one of the factors.
P(1) = 1³+1²-(4x1)-4 = -6 ≠ 0
P(-1) = (-1)³+(-1)²-(4x-1)-4 = 0 Therefore (x+1) is a factor.

However if the cubic polynomial i am trying to solve is P(x) = 3x³-8x²-17x+14 it would take a long amount of time to find one of the factors.
P(1) ≠ 0
P(-1) ≠ 0
P(2) ≠ 0
P(-2) ≠ 0
P(7) ≠ 0
P(-7) ≠ 0
After a long period of time you would find that P(3/2) = 0 Therefore (3x-2) is a factor. Surely there is a much quicker way?