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Thread: [RESOLVED] Trouble with inet.openurl after failed connection

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  1. #1

    Thread Starter
    New Member
    Join Date
    Jul 2007
    Location
    Manchester, England
    Posts
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    Resolved [RESOLVED] Trouble with inet.openurl after failed connection

    Hi,

    I'm writing a little application which uses inet.openURL to bring back a variable from a number of remote systems.

    I've come across a strange issue where if it fails on connection to one of the systems, for the next system it attempts it doesn't seem to do anything at all?

    Here is some example code (I've also uploaded the demo app) where I have 5 different sites to connect to, sites 3 and 4 do not exist.

    If you click on site1, it will bring back a result ok.
    If you click on site3, it will bring back an error ok.
    Now that we've had a failed connection, try clicking either a good or bad site - it does nothing?? It seems to take 2 attempts before it gets the next good or bad result.

    I would really appreciate any help, I've been looking at this for a couple of days and can't see any reason why it's acting in this way.

    Code:
    Private Sub Form_Load()
     Inet1.RequestTimeout = 7
    End Sub
    
    
    Private Sub cmd_check1_Click()
     On Error GoTo Check1Error:
     txt_result1.Text = Inet1.OpenURL(txt_string1.Text)
    Exit Sub
    
    Check1Error:
    txt_result1.Text = Err.Description
    End Sub
    
    
    Private Sub cmd_check2_Click()
     On Error GoTo Check2Error:
     txt_result2.Text = Inet1.OpenURL(txt_string2.Text)
    Exit Sub
    
    Check2Error:
    txt_result2.Text = Err.Description
    End Sub
    
    Private Sub cmd_check3_Click()
     On Error GoTo Check3Error:
     txt_result3.Text = Inet1.OpenURL(txt_string3.Text)
    Exit Sub
    
    Check3Error:
    txt_result3.Text = Err.Description
    End Sub
    
    Private Sub cmd_check4_Click()
     On Error GoTo Check4Error:
     txt_result4.Text = Inet1.OpenURL(txt_string4.Text)
    Exit Sub
    
    Check4Error:
    txt_result4.Text = Err.Description
    End Sub
    
    Private Sub cmd_check5_Click()
     On Error GoTo Check5Error:
     txt_result5.Text = Inet1.OpenURL(txt_string5.Text)
    Exit Sub
    
    Check5Error:
    txt_result5.Text = Err.Description
    End Sub
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