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Thread: bit or'ing question [RESOLVED]

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    Hyperactive Member voidflux's Avatar
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    bit or'ing question [RESOLVED]

    Hello everyone.

    I had a quick question for the following

    Assume $t0 holds 0x12001F10 after executing the instruction 'ori $t0, $t0, 784', which is the possible value of $t0 before executing this instruction?

    A. 0x12001B11
    B. 0x12000C00
    C. 0x12001B10
    D. 0x12001C00

    The answer is infact D.

    But i must have made a lucky guess i thought u solved this problem by doing the following:

    converting 0x12001F10 to binary, and then converting each of A-D and or'ing each one with $t0, and if you come out with the address in $t0 = 0x12001F10 you've selected the right one. But if u say convert B to binary and or that with $t1 you still come out with $t1 even though B is inncorrect so that can't be the method. So i thought maybe you convert the number 784 and or that with the value in $t1, but this is also incorrect, you'll just end up getting 0x12001F10 which isn't even a choice but its what u started out with.


    So finally I converted 784 to binary and or'ed that with each poisslbe answer and I figured it out while typing this message. Is there an easier way to get the answer rather than just elimination? On the exam i doubt i will have enough ttime to convert each choice to its equivlent binary form and or it with the number given if she has more than 4 choices.

    Code:
    0000 0000 0000 0000 0011 0001 0000  784
    0001 0010 0000 0001 1110 0000 0000  0x12001C00
    0001 0010 0000 0001 1111 0001 0000  ori
    1        2     0      1      F      1       0
    which is what $t0 holds
    Last edited by voidflux; Oct 9th, 2006 at 12:03 PM.
    C¤ry Sanchez
    Computer Science/Engineering
    @ Penn State
    IBM.zSeries Intern
    Mandriva 2007

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