[Resolved]adding even or odd numbers in array, MIPS32

[voidflux]

Hello everyone. I go this program to add up all the elements in the array and dispaly its value, but now i'm trying to add up only even numbers if the user enters 0. If they don't enter 0, then it will add up all the odd and dispaly the sum. Store result in register $t1.

Here is the code i have to add up all the elements in the array:

.data
.align 2
item: .word 1
.word 2
.word 3
.word 4
.word 5
.word 6
.word 7
.word 8
.word 9
.word 10
.align 0
str: .asciiz "The answer is "
cr: .asciiz "\n"
.text
.align 2
.globl main
main: ori $2, $0, 5
syscall
move $t0, $2


li $t2, 0            #i=0

loopsum:
    bge $t2, 10, done    #while (i < 10)
    mul $t3, $t2, 4        #4*i
    la $t4, item        #calculate &item[i] address
    add $t3, $t3, $t4
    lw $t5, 0($t3)        #load item[i] into $t5
    

    add $t1,$t1,$t5        #$t1 = $t1 + item[i]
    add $t2, $t2, 1        #i++
b    loopsum




done: ori $2, $0, 4
la $4, str
syscall
ori $2, $0, 1
add $4, $t1, $0
syscall
ori $2, $0, 4
la $4, cr
syscall 

This will print The answer is: 55.

Now i'm having alot of trouble on how i can implement this in asm. What i want is:

if(userinput == 0)
loop through array if(item[i] % 2 == 0) { $t1 = $t1 + item[i] };
else
loop through array if(item[i] % 2 != 0) { $t1 = $t1 + item[i] };

So if the user inputs 0, that means sum up all the even numbers in the array
else
sum up all the odd numbers in the array.

Will this work to check to see if the remainder is 0? (if it is 0, then u konw its an even number.)

lw $t5, 0($t3)        #load item[i] into $t5
    
    ori $t6, $0, $t5    #t6 = $t5
    div $t6,2        #$HI = $s % $t    
beq $HI,0,loopeven    # if ($t6 % 2) == 0, even number 

THanks!