Hello good VB people,

Now I know that you can do things like

5/(x+4)(x-3) = A/(x+4) + B/(x-3)

or

3/(x²+2)(x+4) = (Ax + B)/(x²+2) + C(x+4)

but can you apply the same idea to sin(ax)/sqrt[(x-k)(x+k)] ??

For example

sin(ax)/sqrt[(x-k)(x+k)] = Asin(ax)/sqrt(x-k) + Bsin(ax)/sqrt(x+k)

Even if you can apply the same theory, I wonder what form the RHS should take. Perhaps

sin(ax)/sqrt[(x-k)(x+k)] = (Ax + B)sin(ax)/sqrt(x-k) + (Cx + D)sin(ax)/sqrt(x+k) ???




Any imput would be appreciated, as I may be about to make a major breakthrough with the integral

INT[ sin(ax)/sqrt{(x-c)² + b} ] dx

which has thus far eluded my friend and I. It looks like it should be easy, but not even Mathematica or Maple produce an answer in terms of kown functions.


Ok cheers, Mattywoo