Hey,

Ok, i have got the equation:

(((X * X) - X) - 1) = 0

"X Squared, Minus X, Minus 1"

What i have to do is work out what x is to make 0 so say 3*3 - 3 - 1 etc. Does anyone know the answer or an program that will work out the answer. I have this:

#include <iostream.h>

void main (void)
{
float cur;
float x;
char *temp;

cur = 0.0;

do
{
cur = cur + 0.0000000000000000000000000000000000000001;

x = (((cur * cur) - cur) - 1);

cout << cur << "\t" << x << endl;

}while (x != 0);

cin >> temp;
}

but im not sure if thats working properly. It can be in vb or c++ but i just need to find what valuse X has to be so that X squared, minus X, minus 1 is equal to 0.

Thanks