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Dec 8th, 2004, 07:15 PM
#1
Thread Starter
PowerPoster
[RESOLVED]Find the equation of the axis of symmetry and the vertex of x
Hey guys. This has to do with Porabala's and finding the Vertex and axis of symmetry. I know the basic function of how to do it, but I am not coming up with the correct answer.
Here is the equation x = -3y2 + y + 4
Now, I have found the y coordinate which is -1/6. Now I need to find the Vertex which is (? , -1/6).
Basically all that has to be done is replace the y's in the equation with -1/6, but for some reason I am having trouble getting the correct answer.
Any help is appreciated!
Last edited by Arc; Dec 8th, 2004 at 09:39 PM.
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