Hi,
If I run the following line in the RUN dialog box (i.e. start, run window) it works fine (Notice the double quotes at the beginning, middle and the end):
"\\W-I55ZB6B7\c$\Program Files\game" \\psiukapp6\test.zip ckff.ckff.asc \\W-I55ZB6B7\c$\test"


but when this line is created in c# it is not quite the same (Notice the double quotes) and therefore I can not run it using System.Diagnostics.Process.Start

strLine = @"\\W-I55ZB6B7\c$\Program Files\game \\psiukapp6\test.zip capt.capt.asc \\W-I55ZB6B7\c$\test"

System.Diagnostics.Process.Start(strLine)

The error is: system can not find the file specified.

How is it possible to make the c# created string as same as the one which can be run in the RUN dialog box?
Thanks