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Jan 16th, 2004, 06:46 PM
#30
Thread Starter
Fanatic Member
okay I get it now
k1 >> 3
is actually
k1 /( 2^3)
and
1 << 7
is
1 * 2 ^ 7
thank you for helping me understand that
now I have another issue
for some reason vb doesn't have XOR as a syntax?
even 10 XOR 10 the XOR is giving me an error?
is there any way to create an XOR like function?
thanx.
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