this code could be shorter . . .

[fundean]

something tells me this code could be shorter.

can anyone suggest a shorter algorithm?

//Allows user to enter a word, then displays whether or not the word is a palindrome (same forwards and backwords)

#include <iostream.h>
#include <apstring.h>

void main()
{
apstring word;
int a,c,e;
cout<<"Enter a word: ";
cin>>word;
a=word.length();
a--;
for (c=0;c<a;c++)
{
if (word[c]!=word[a])
{
cout<<"That word is not a palindrome."<<endl;
e=-1;
c=a+5;
}
a--;
}
if (e!=-1)
cout<<"That word is a palindrome."<<endl;
}