|
-
May 2nd, 2002, 08:23 AM
#1
-
May 2nd, 2002, 08:25 AM
#2
x1=(b*b +sqr( (-4)*a*c)) /2
x2=(b*b -sqr( (-4)*a*c)) /2
Hope this helps,
-
May 2nd, 2002, 08:26 AM
#3
Fanatic Member
that finds the roots of a parabola.
-
May 2nd, 2002, 08:29 AM
#4
Rofl, parabola yea...
If you will the graph it will be a parabola but how can i write the marked part in the pic ive attached in VB?
You sure i can do it with 'sqr'?
-
May 2nd, 2002, 08:31 AM
#5
Bouncy Member
-
May 2nd, 2002, 09:14 AM
#6
Maths was invented by God, but adopted by the Devil!
Oooo...Quadratic equations...That takes me back to GCSE maths 
Glad you weren't asking to solve a 3D Intergration formula...*shudder*
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|