Unsigned Numbers (Binary Arithmetic)

[abhijit]

Hi Everybody,
I have written two functions which allow you to convert binary numbers to decimals and decimals to binary. I haven't yet added any support for unsigned numbers, but soon will. Meanwhile if there are any ideas for shrinking the code, they are most welcome.
Cheers!
Abhijit

Private Function To_Decimal(vValue As Variant) As Long
    Dim sValue As String
    Dim lLenValue As Long
    Dim lReturnVal As Long
    Dim aIndices(8) As Long
    aIndices(0) = 2 ^ 0
    aIndices(1) = 2 ^ 1
    aIndices(2) = 2 ^ 2
    aIndices(3) = 2 ^ 3
    aIndices(4) = 2 ^ 4
    aIndices(5) = 2 ^ 5
    aIndices(6) = 2 ^ 6
    aIndices(7) = 2 ^ 7
    
    sValue = CStr(vValue)
    lLenValue = Len(sValue)
    If lLenValue < 8 Then
        Do Until Len(sValue) = 8
            sValue = "0" & Left(sValue, Len(sValue))
        Loop
    End If
    
    Dim iIndexPosition As Integer
    iIndexPosition = 0
'    Now Start from the most side bit and decrement
    For lLenValue = 8 To 1 Step -1
        Debug.Print sValue & " ---> " & Mid(sValue, lLenValue, 1)
        lReturnVal = lReturnVal + (CLng(Mid(sValue, lLenValue, 1)) * aIndices(iIndexPosition))
        iIndexPosition = iIndexPosition + 1
    Next lLenValue

    To_Decimal = lReturnVal
End Function
Private Function To_Binary(iInputNo As Integer) As String
    Dim aBitValues(7) As Integer
    aBitValues(0) = 128
    aBitValues(1) = 64
    aBitValues(2) = 32
    aBitValues(3) = 16
    aBitValues(4) = 8
    aBitValues(5) = 4
    aBitValues(6) = 2
    aBitValues(7) = 1
    Dim iArrCounter As Integer
    Dim sReturnValue As String
    For iArrCounter = 0 To UBound(aBitValues)
        If iInputNo < aBitValues(iArrCounter) Then
            sReturnValue = sReturnValue & "0"
        Else
            sReturnValue = sReturnValue & "1"
            iInputNo = iInputNo - aBitValues(iArrCounter)
        End If
    Next iArrCounter
    
        To_Binary = sReturnValue
    
End Function

[abhijit]

Thanks for your suggestion.
I am going to implement those. I read your reply in both my threads.

Cheers!
Abhijit