How to filter preg_match_all result

[tony007]

Hi all .i am using the following code to get the image thumb and url from a remote html .The code is working but the problem is that it outputs some unwanted images !! could any one help me so i can output only those images that are like the give html and omit the rest.Thanks

$photos = "http://www.somesite.com/images.html";
    
    curl_setopt($ch, CURLOPT_URL, $photos);
    curl_setopt($ch, CURLOPT_POST, 0);
    $pagecontents = curl_exec($ch);

 

        $pattern = "/src=[\"‘]?([^\"’]?.*(png|jpg|gif))[\"’]?/i";
        preg_match_all($pattern, $pagecontents, $matches);
    
    $count = count($matches[1]);
        
        echo $count; 

html of images to consider:

   <div class="photo_index_item">
                            <div id="dvImgListHypImage">
                            <a id="ctl00_cpMain_UserViewPictureControl_ImageListings1_dlImageList_ctl14_hypImage" title="image name" class="photo_image" href="http://www.somsite.com/imagelink2"><img title="image name" src="http://www.somesite.com/m_d1288db7a7c2ab5c34b521ac62eb3e43.jpg" style="border-width:0px;" /></a>
                            </div>

[RudiVisser]

foreach($matches as $key => $match) {
    if(!preg_match("the html you want to match", $match)) {
        unset($matches[$key]);
    }
} 

[tony007]

Rudi thanks for your reply. could you explain to me how it works ? i don't know what you mean by the html you want ot match ? All i want to collect http://www.somesite.com/m_d1288db7a7...ac62eb3e43.jpg

only when it appears with in <div> only and omit the rest of images that are outside of <div>

[RudiVisser]

   <div class="photo_index_item">
                            <div id="dvImgListHypImage">
                            <a id="ctl00_cpMain_UserViewPictureControl_ImageListings1_dlImageList_ctl14_hypImage" title="image name" class="photo_image" href="http://www.somsite.com/imagelink2"><img title="image name" src="http://www.somesite.com/m_d1288db7a7c2ab5c34b521ac62eb3e43.jpg" style="border-width:0px;" /></a>
                            </div>

Well you posted this so I assume you mean this.

I don't see why you just don't alter your original expression to have the containing <div> though.