Help check this for me?

[Yunie]

What's the derivative of

(e^x - e^(-x)) / (e^x + e^(-x))???

My answer is (e^2x + e^-2x) - (e^2x + e^-2x)/ (e^x + e^-x)2

Correct? If not, can show me your workings?

[krtxmrtz]

What's the derivative of

(e^x - e^(-x)) / (e^x + e^(-x))???

My answer is (e^2x + e^-2x) - (e^2x + e^-2x)/ (e^x + e^-x)2

Correct? If not, can show me your workings?

I don't think so. Show us your workings so we can see where you stumbled.

[eranga262154]

What's the derivative of

(e^x - e^(-x)) / (e^x + e^(-x))???

My answer is (e^2x + e^-2x) - (e^2x + e^-2x)/ (e^x + e^-x)2

Correct? If not, can show me your workings?

Your answer is wrong. Seems to me you are conflict with +/- signs. And also on following derivative.

e^axb would be.. (ab)e^axbx^{(b - 1)}

I think it is clear for you. Try again.

[krtxmrtz]

Your answer is wrong. Seems to me you are conflict with +/- signs. And also on following derivative.

e^axb would be.. (ab)e^axbx^{(b - 1)}

I think it is clear for you. Try again.

I think this example may not be too convenient... you are using e^f(x) where f(x) is another function, but she only has to deal with e^x and e^-x so why complicate it further? By the way, the original function is Th(x) the hyperbolic tangent of x.

[eranga262154]

Actually I'll never try to make further complex this. What I'm trying to say is that given explanation is the basis. If you clear on it, easy to deal. According to Yunie's both a and b are equal to one.

Basically he is going wrong with +/- signs, I think.