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Sep 7th, 2007, 04:29 AM
#1
Thread Starter
Lively Member
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Sep 7th, 2007, 04:44 AM
#2
Re: Equation
What does a generic quadratic look like when factorised? What must be true if there is only one root? What do you get when you expand out of the brackets?
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Sep 7th, 2007, 05:02 AM
#3
Thread Starter
Lively Member
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Sep 7th, 2007, 05:24 AM
#4
Re: Equation
For quadratic equations in the form of:
0= x^2 +px +q
The two possible solutions for x are (using the so called pq-formula):
x1= -p/2 + squareroot( (p/2)^2 -q)
x2= -p/2 - squareroot( (p/2)^2 -q)
In your case there shall be only one solution, in this case the squareroot-part has to be 0. But this can only be true if (p/2)^2=q.
I hope you can take from here!
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Sep 7th, 2007, 06:12 AM
#5
Re: Equation
 Originally Posted by Yunie
Haha...I don't know how to answer your above 3 questions cos I don't really understand......
I think zaza means you're not going to get too far if you don't understand the theory.
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