form.show problem

[King Abadon]

i have to make a pocket aplication
i read from an xml file and i modify some data

private void button1_Click(object sender, EventArgs e)
{
System.Data.DataSet DSet = new DataSet();
DSet.ReadXml("Employee.xml");
dataGrid1.DataSource = DSet.Tables[0];
}
private void button2_Click(object sender, EventArgs e)
{
Form1 Form2 = new Form1();
Form2.Show();//using ShowDialog is teh same
Form2.Activate();

the problem is i cant switch to form2 where i have a textbox and a buton
and if you can please tell me how i can insert the value in the dataset


Sr for so many questions but i'm a rookie with C#

[Paul M]

I don't use C# much but

Form2.ShowDialog

Maybe?

[Shuja Ali]

The code for initializing Form2 and showing it would be

Form2 newForm= new Form2();
newForm.Show();
newForm.Activate();

[ComputerJy]

The code for initializing Form2 and showing it would be

Form2 newForm= new Form2();
newForm.Show();
newForm.Activate();

That'd be right if there was a Form2 class.
And by the way, you don't have to use newForm.Activate(); because it's called from the inside of Form.Show()