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Nov 7th, 2006, 11:35 AM
#1
Thread Starter
New Member
partial differentiation
hi guys wondering if u could help.
iv got a question that involves partial differentiation but it involves doing it from first prinicples
i kno the way to do normal differentiation from first principles....
dy/dx = limit as h tends to zero [f(x+h) - f(x)]/h etc etc
however i dont know what to do when its partial differentiation
the function is f(x,y,z) = 2(x^2 +z)y + x/(z^2)
hope u can help me!
rcd
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Nov 8th, 2006, 12:39 AM
#2
Member
Re: partial differentiation
do you understand how you differentiate like x^2 without the limit formula?( x^2 becomes 2x.)
you need to know that before you can do partial differentiation.
When it is partial differentiation you differently 3 different times for you equation.
one for x, one for y and one for z.
for the x equation you differentiate 2(x^2 +z)y + x/(z^2) treat X as the variable and treat y&z as constants.
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Nov 8th, 2006, 12:42 AM
#3
Member
Re: partial differentiation
Fx=(4·x·y·z^2 + 1)/z^2
Fy=2·(x^2 + z)
Fz=2·(y·z^3 - x)/z^3
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Nov 8th, 2006, 07:00 AM
#4
Thread Starter
New Member
Re: partial differentiation
i am fully aware how to partially differentiate functions however i am being asked to do it from 1st principles and this is what is causing me problems.
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Nov 8th, 2006, 09:47 AM
#5
Addicted Member
Re: partial differentiation
It works the same way as normal differentiation from first principles as the other variables are treated as constants.
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