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Thread: partial differentiation

  1. #1

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    partial differentiation

    hi guys wondering if u could help.

    iv got a question that involves partial differentiation but it involves doing it from first prinicples

    i kno the way to do normal differentiation from first principles....

    dy/dx = limit as h tends to zero [f(x+h) - f(x)]/h etc etc

    however i dont know what to do when its partial differentiation

    the function is f(x,y,z) = 2(x^2 +z)y + x/(z^2)

    hope u can help me!

    rcd

  2. #2
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    Re: partial differentiation

    do you understand how you differentiate like x^2 without the limit formula?( x^2 becomes 2x.)
    you need to know that before you can do partial differentiation.

    When it is partial differentiation you differently 3 different times for you equation.
    one for x, one for y and one for z.
    for the x equation you differentiate 2(x^2 +z)y + x/(z^2) treat X as the variable and treat y&z as constants.

  3. #3
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    Re: partial differentiation

    Fx=(4·x·y·z^2 + 1)/z^2
    Fy=2·(x^2 + z)
    Fz=2·(y·z^3 - x)/z^3

  4. #4

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    Re: partial differentiation

    i am fully aware how to partially differentiate functions however i am being asked to do it from 1st principles and this is what is causing me problems.

  5. #5
    Addicted Member Glaysher's Avatar
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    Re: partial differentiation

    It works the same way as normal differentiation from first principles as the other variables are treated as constants.
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