Prove the following identities. c) (tanx sinx)/tanx - sinx = (tanx + sinx)/(tanx sinx)
It's been a while since I did similtaneous equations but here goes. c) (tanx sinx)/tanx - sinx = (tanx + sinx)/(tanx sinx) tanx sinx = (tanx + sinx)/(tanx sinx) + sinx * tanx tanx = (tanx + sinx)/(tanx sinx) + sinx - (tanx sinx) sinx = (tanx + sinx)/(tanx sinx) * tanx - (tanx sinx)
Originally Posted by fiery123 Prove the following identities. c) (tanx sinx)/tanx - sinx = (tanx + sinx)/(tanx sinx) RHS (tanx + sinx)/(tanx sinx) = tan x/[tan x sin x] + sinx/[tan x sin x] = 1/sin x + 1/tan x = 1/sin x + cos x/sin x = [1 + cos x]/sin x LHS (tanx sinx)/[tanx - sinx] = tan x/[(1/cos x) - 1] = sin x/[1 - cos x] = sin x[1 + cos x]/[1 - cos2 x] = sin x[1 + cos x]/sin2 x = [1 + cos x]/sin x So LHS = RHS
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thanks thanks a lot. sry about forgeting to put brackets around tanx-sinx.
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