Possible Syntax Error?

[ChR0NiC]

$query = "SELECT * FROM helpfultips";
$result = mysql_query($query);

$i = 0;

while($row = mysql_fetch_array($result))
{
extract($row);

$tipsy[i] = $tip;

$i++;

}

$tipnum = rand(0, $i);

echo $tipsy[$tipnum];

I have this helpful tips table which has tips to be randomized every time you changed the page. But it won't show the tip! If I put the echo up in the loop it works but then it shows all of the tips, I only want one random one. I don't understand why it won't work, this has never happened to me before. Does anybody see a reason why it wouldn't work?

[kows]

you aren't assigning your array a correct index. you're using i when you should be using $i. only thing I could think of. never used extract() with a query before, so if it still isn't working or if that was just some typo on your part, you can always try using $row['tip'] instead.

[ChR0NiC]

Wow, I can't believe I made such a simple mistake. What the hell was I thinking? That was exactly the problem, I am almost embarrassed.... I had a late night last night, but THANK YOU SO MUCH

[CornedBee]

Set your PHP warning level to emit warnings, and even notices. This shouldn't have gone unnoticed. (Pun not intended.)