Application.startuppath

[steve_rm]

Hello,

I want to be able to edit a file. The file will be located in the same directory as the setup.exe. However when the program is run it does work when i use the application.startupath. However, when I don't use it works ok. Can anyone explain how this should work.

fileMap.ExeConfigFilename = Application.StartupPath & "\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy" 'Not work
            fileMap.ExeConfigFilename = "C:\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy" 'Works ok

            config = ConfigurationManager.OpenMappedExeConfiguration(fileMap, ConfigurationUserLevel.None)

Many thanks in advance,

Steve

[Riks]

Did you print Application.StartupPath to confirm that it infact is: "C:\CodeRed6" ?

[maps]

Is the return type for ExeConfigFilename as string?
If it is, try
fileMap.ExeConfigFilename = ".\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy"

[jmcilhinney]

Surely Application.StartupPath will be returning "C:\CodeRed6\CodeRed_1_0_0_10".

[josep]

According your code I assume your exe is on the

C:\

if that's true application.startuppath returns you c:\

so your path is

c:\\CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy

which returns you an error

Try that

If not Application.StartupPath.EndsWith("\") Then
             fileMap.ExeConfigFilename = Application.StartupPath & "\"
        End If
fileMap.ExeConfigFilename &= "CodeRed6\CodeRed_1_0_0_10\CodeRed.exe.config.deploy"

Hope this helps

[maps]

JMC has given you the right answer. You need to just append it with the string of your file name.
Disregard what i wrote earlier.

[josep]

Hi again

As usual JMC points on the right direction

Just check this tread (or have a look on the help) to know what is returning the startuppath method and concatenate the right string to get the path (or file) relative to startuppath of you application

[steve_rm]

Hello,

I thought I had this resolved.

The problem is this. I have deployed a program in the folder where the setup file is, I have a folder called CodeRed_1_0_0_10, inside that folder I have a file called CodeRed.exe.config.deploy. I want to be able to access this file.
The path is this:
C:\Deployed_4_10_06\CodeRed_1_0_0_10.

The setup.exe file is located in the Deployed_4_10_06 folder. I thought by using application.startuppath would point to this directory. However, after checking I found out that is points to this one below:

C:\Documents and Settings\yasin\Local Settings\Apps\2.0\YDBGO2AL.YA3\TOMO6HER.GJR\code..tion_53e3de40adb22891_0001.0000_adfb41cfb825f353

I thought by using this:
path = Application.StartupPath & "\CodeRed_1_0_0_11\" & "CodeRed.exe.config.deploy"

I would be able to update my file, but cannot not.

Is there a way to be able to point to the file where the setup.exe is located?

Many thanks in advance,

Steve

[jmcilhinney]

It looks very much like you're publishing your app using ClickOnce. One of the advantages of ClickOnce is that it has in-built auto-update functionality. You should head to MSDN and read up on ClickOnce and what it can and can't do.