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Thread: Linear programming problem

  1. #1

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    Linear programming problem

    I got a LP problem that I'm stuck on.

    A furniture factory makes tables and chairs. It takes 2 hours to assemble a table and 30 minutes to assemble a chair. Assembly is carried out by four people on the basis of one eight-hour shift per day. Customers buy at four chairs with each table which means that the factory has to make at most four times as many chairs as tables. The selling price is €135 per table and €50 per chair.

    Formulate this as a linear programming problem to determine the daily production of tables and chairs which would maximise the total daily revenue to the factory and solve the problem using the simplex method.

    My progress:

    X1 = Amount of tables produced
    X2 = Amount of chairs produced

    Max Z = 135X1+50X2

    Subject to:
    120X1+30X2 ≤ 1920
    4X1 ≥ X2
    X1, X2 ≥ 0

    Standard form:

    Max Z = 135X1+50X2

    Subject to:
    4X1+X2+S1 = 64
    4X1-X2-S2 = 0
    X1, X2, S1, S2 ≥ 0

    Are my constraints correct?



    Thanks for your time.
    Last edited by fobster; Aug 20th, 2006 at 04:45 AM.

  2. #2
    Addicted Member Rassis's Avatar
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    Re: Linear programming problem

    Yes, they are correct and the result must be 8 tables and 32 chairs selling for €2,680.

    Try to reach these same conclusions yourself using the simplex method.
    ...este projecto dos Deuses que os homens teimam em arruinar...

  3. #3
    Addicted Member Glaysher's Avatar
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    Re: Linear programming problem

    Actually there is a minor error

    4X1+X2+S1 = 1920

    should be either

    120X1+30X2+S1 = 1920

    or

    4X1+X2+S1 = 64

  4. #4

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    Re: Linear programming problem

    Quote Originally Posted by Glaysher
    Actually there is a minor error

    4X1+X2+S1 = 1920

    should be either

    120X1+30X2+S1 = 1920

    or

    4X1+X2+S1 = 64
    Just a typo by me.

  5. #5
    Addicted Member Glaysher's Avatar
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    Re: Linear programming problem

    Then you are fine

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