Ok i have this script
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/sttimy/public_html/index.php on line 5Code:<? mysql_connect("127.0.0.1", "sttimy", "******")or die(mysql_error()); mysql_select_db(site); $conline = mysql_query("SELECT COUNT(Username) FROM Useraccount where online='1'"); $online = mysql_result($conline,0); echo $online; ?>
That is the error i get, i don't know why because i have another script that has almost the exact same code but it works.
EDIT:
Well i read another topic and it said to use mysql_error() to find out their specific error so i did that and found out that my table Useraccount didn't exist. Well Useraccount didn't but Useraccounts did so i just fixed it up.


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