[Resolved] DateDiff problem

[solitario]

Hello all. I found the following code which will display the number of days between two dates. The problem is if I take out the "SEP" and replace it with say 9 or 09 it doesn't work.
How would I rewrite this so that I can use all numeric values.
All the dates in my database use yyyy-mm-dd format if that helps.

$today=date("d-m-Y");
$date1=strtotime( "1-SEP-2005");

$date2=strtotime($today);

	echo "Difference: ".(($date2-$date1)/86400);

Many thanks.

[solitario]

Got it.

function datediff($start_date, $end_date) {
	list($start_date_month, $start_date_day, $start_date_year) = split('[/.-]', $start_date); 
		if (!$end_date) {
			$end_date_year = date("Y");
			$end_date_month = date("m");
			$end_date_day = date("d");
		} else {
			list($end_date_month, $end_date_day, $end_date_year) = split('[/.-]', $end_date);
		}
			$start_date = mktime(0,0,0,$start_date_month, $start_date_day, $start_date_year);
			$end_date = mktime(0,0,0,$end_date_month, $end_date_day, $end_date_year);
			$difference = $end_date-$start_date;
				return floor($difference/60/60/24);
}