ACCESS: How To: Set Label Caption in a Report [RESOLVED: OpenArgs]

[Webtest]

Esteemed Forum Participants and Lurkers:
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ACCESS '02, '03

I have a common Report format for 4 different Departments, and in the code with the 'Department Selector' buttons I am trying to change one of the Labels in the report "Page Header" to reflect the different department selection. I have tried many approaches, but nothing seems to work yet. Here is what I am working with now:

Added Note: The following code does PRINT correctly, and it also displays correctly on pages 2 and above for multiple pages. It just doesn't affect Page 1 displayed in a window!!!

Private Sub Command0_Click()
    Dim aWhere As String
    'Select a WHERE statement (from Global List) based on the Radio Button Group
    aWhere = aDept(Form1.Grp_Dept.Value)
    
    'This successfully opens a window with the correct Report
    DoCmd.OpenReport "Price_1", acViewPreview, , aWhere, acWindowNormal
    
'''TEST TEST TEST TEST    This WORKS
MsgBox Reports("Price_1").Controls("Dpt_Label").Caption
'''END TEST

    'Can a Report be changed once it is open???  This doesn't change anything!
    Reports("Price_1").Controls("Dpt_Label").Caption = "TEST 1"
    
End Sub

Any and all comments, suggestions, and assistance is sincerely appreciated.

[Webtest]

Hey, MethadoneBoy's question about passing a parameter was the inspiration I needed!

I solved the problem by passing the new text for the Label.Caption in the "OpenArgs" parameter in the OpenReport command, and used the Open Event for the Report to install the new Caption. It works great!

'>>>    In Control Form Module
Private Sub Command0_Click()
    Dim aWhere As String
    Dim aStrArg As String
    
    'Select a WHERE statement (from Global List) based on the Radio Box Group
    aWhere = aDept(Me.Dpt_Chain.Value)
    'Pass a String Argument to the Report to install in the Label
    aStrArg = "TEST 22"
    'Open the Report and pass it a string ...
    DoCmd.OpenReport "Price_1", acViewPreview, , aWhere, acWindowNormal, aStrArg
   
End Sub

'>>>    In Report Code  -  Form opens with "TEST 22" in the Label
Private Sub Report_Open(Cancel As Integer)
  
  If Not IsNull(Me.OpenArgs) Then
      Me.Controls("Dpt_Label").Caption = Me.OpenArgs
  End If
  
End Sub