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Thread: Some basic bouncing

  1. Feb 27th, 2005, 01:37 AM #1
    Halsafar
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    Some basic bouncing

    F=ma
    a=F/m

    I hit the ground with a velocity on the y axis of 50 m/s. Accelerating simply with gravity (9.81)
    Newtons third law, any force has an equal opposing force. So I hit the ground going 50m/s, for some basic bouncing (very basic) shouldn't I be able to take the current velocity, acceleration and somehow determine the new force to push upward.
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  2. Feb 27th, 2005, 07:01 PM #2
    Phenix
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    Re: Some basic bouncing

    Yes.
    For perfectly elastic collisions (read as fiction/fantasy), the new velocity is 50 m/s.

    Also, before hitting the ground, your sign should be negative if up is positive for your axis. -50 m/s before, and +50 m/s after.

    Again, if up is positive (I believe for your application) gravity acceleration is always constant at -9.81 m/s2.

    I think you will like this java applet at this site. I didn't check it out completely, but it looks like you can adjust elasticity and gravity, etc.
    http://www.myphysicslab.com/collision.html

    Edit: Their gravity is positive instead of negative at the website
    Last edited by Phenix; Mar 18th, 2005 at 05:37 PM. Reason: Gravity sign
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