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Thread: I am back

  1. #1

    Thread Starter
    Hyperactive Member mudfish's Avatar
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    Resolved I am back

    Find the maximum value:
    f(t) = -16t^2 + 48t + 300

    Solve the exponential equation for t:
    5 = 10e^-.00002845t
    Last edited by mudfish; Dec 9th, 2004 at 08:10 AM.
    Mudfish AKA Bowfin
    I can spell "If" all day right, just a coder!


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  2. #2
    Retired G&G Mod NoteMe's Avatar
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    Re: I am back

    First derivate the first thingy:


    f ' (t) = -32t + 48


    Then set that one = zero

    -32t + 48 = 0

    32t = 48

    t = 48/32
    t = 3/2


    thats where t is max/min

    Now put t into the first thingy and see what you get.

    f(3/2) = -16*(3/2)^2 + 48*(3/2) + 300

    No idea what that is....and you are not getting me to find some peace of paper to calculate it either..


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  3. #3
    type Woss is new Grumpy; wossname's Avatar
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    Re: I am back

    I just interpolated with my calculator...

    Max is where x=1.5, y=336
    I don't live here any more.

  4. #4
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    Re: I am back

    5 = 10e^-.00002845t

    divide both sides by 10

    1/2 = e^-.00002845t

    take natural logs

    ln(1/2) = -.00002845t

    or (since -ln(2) = ln(1/2)):

    t = ln(2)/.00002845
    an ending

  5. #5

    Thread Starter
    Hyperactive Member mudfish's Avatar
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    Re: I am back

    Thanks for the help, she want me to check her work!

    She knows I not had math in 18 years.
    Mudfish AKA Bowfin
    I can spell "If" all day right, just a coder!


    "Always do sober what you said you'd do drunk. That will teach you to keep your mouth shut." -- Ernest Hemingway

    Member of the ECCC

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