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Dec 8th, 2004, 06:48 PM
#1
Thread Starter
Hyperactive Member
I am back
Find the maximum value:
f(t) = -16t^2 + 48t + 300
Solve the exponential equation for t:
5 = 10e^-.00002845t
Last edited by mudfish; Dec 9th, 2004 at 08:10 AM.
Mudfish AKA Bowfin
I can spell "If" all day right, just a coder!
"Always do sober what you said you'd do drunk. That will teach you to keep your mouth shut." -- Ernest Hemingway
Member of the ECCC

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Dec 8th, 2004, 07:15 PM
#2
Re: I am back
First derivate the first thingy:
f ' (t) = -32t + 48
Then set that one = zero
-32t + 48 = 0
32t = 48
t = 48/32
t = 3/2
thats where t is max/min
Now put t into the first thingy and see what you get.
f(3/2) = -16*(3/2)^2 + 48*(3/2) + 300
No idea what that is....and you are not getting me to find some peace of paper to calculate it either..
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Dec 9th, 2004, 04:24 AM
#3
Re: I am back
I just interpolated with my calculator...
Max is where x=1.5, y=336
I don't live here any more.
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Dec 9th, 2004, 05:39 AM
#4
Fanatic Member
Re: I am back
5 = 10e^-.00002845t
divide both sides by 10
1/2 = e^-.00002845t
take natural logs
ln(1/2) = -.00002845t
or (since -ln(2) = ln(1/2)):
t = ln(2)/.00002845
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Dec 9th, 2004, 08:09 AM
#5
Thread Starter
Hyperactive Member
Re: I am back
Thanks for the help, she want me to check her work!
She knows I not had math in 18 years.
Mudfish AKA Bowfin
I can spell "If" all day right, just a coder!
"Always do sober what you said you'd do drunk. That will teach you to keep your mouth shut." -- Ernest Hemingway
Member of the ECCC

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