Line Plotting and angles

[santosh66]

I am working with line plotting in a form.
I need to find an angle between two lines AB,BC joined at B.
AB and BC lengths are not same.
I know (x,y) values of A,B and C.
How to find angle at B?

and also
I have Trignometric "TanA" value.
How to find angle 'A' ?

in VB code point, can some body help me?

[Ecniv]

sqr((Ax-Bx)^2 + (Ay-By)^2) = length AB
sqr((Cx-Bx)^2 + (Cy-By)^2) = length BC

TanA - isn't that the Arc Tan of an angle ?? Say B?
Or do you mean Tan(A) = degrees/radians?

I'm trying to remember back around ten years

Post up again later


Vince

[wossname]

The sandpaper library will have a derived math class in it. It will contain functions for all the derived math equations detailed in MSDN.

It has already been coded. Alpha Launch date: 01 Dec 04.

[santosh66]

I have a line with known x,y values. that is x1,y1 and x2,y2.
I need to shift that line with same slope and lenght to new point to x3,y3.
that is new line coordinates shall be x3,y3 and x4,y4.
how do I do it in VB point of view. any help pl.

Very Urgent.

[LabtroRob]

x3 - x1 = diffx
y3 - y1 = diffy

x4 = x2 + diffx
y4 = y2 + diffy