help with strings

[nota141]

i have a string with "\" in it i i wanted a way to only get the last bit of test after the last "\" but the string may contain different numbers of "\" can someone help

[nota141]

two examples on data that i need to change

NDS:\\HUB\APHS\ST\95\gmitchell
NDS:\\HUB\APHS\Staff\twest

i need gmitchell and twest

i was thinking i have some code that will give me the cut the string in to two parts. but i will need a while wend to cheack if the string still contains "\".

[HeSaidJoe]

'if you have VB6
Private Sub Form_Load()
    Dim x As String
    x = "my/and that/and mylast/is not only a / but it was last"
    Dim y
    y = Split(x, "/")
    MsgBox y(UBound(y))
End Sub

'split function for VB5 and under   vb6 has the function
'posted originally by Aaron Young

Public Function Split2(ByVal sString As String, ByVal sSeparator As String) As Variant
    Dim sParts() As String
    Dim lParts As Long
    Dim lPos As Long
    
    lPos = InStr(sString, sSeparator)
    While lPos
        ReDim Preserve sParts(lParts)
        sParts(lParts) = Left(sString, lPos - 1)
        sString = Mid(sString, lPos + Len(sSeparator))
        lPos = InStr(sString, sSeparator)
        lParts = lParts + 1
    Wend
    If Len(sString) Then
        ReDim Preserve sParts(lParts)
        sParts(lParts) = sString
    End If
    Split2 = IIf(lParts, sParts, Array())
End Function

'Example:

Private Sub Form_Load()
    Dim x As String
    x = "my/and that/and mylast/is not only a / but it was last"
    Dim y
    y = Split2(x, "/")
    MsgBox y(UBound(y))
End Sub

[nota141]

this is the code that i found all i need to do is put a while wend loop around it to check if there is still "\" in the string.

result1 = Left$(tempstr, InStr(1, tempstr, "\", vbTextCompare))
tempstr = Right$(tempstr, Len(tempstr) - Len(result1))
result1 = Left$(result1, Len(result1) - 1)

[iring]

It is mucht easier. Just use the function InstrRev.