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Thread: folding squares..geometry SOLVEDO

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    folding squares..geometry SOLVEDO

    When this net of six squares is cut out and folded to form a cube, what is the product of the numbers on the four faces adjacent to the one labeled 1?

    Last edited by dolor; Apr 10th, 2004 at 11:22 PM.
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    good show
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    Fanatic Member alkatran's Avatar
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    2*3*4*6=6*6*4 = 6*6*2*2=12*12=144

    Is a hyper cube a 4 dimensional object? How is it represented?

    Here's how I represent a cube on 2d, I'd love to see a 4d object.
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    Originally posted by alkatran
    I'd love to see a 4d object.[
    well, you'd be rich if you could, seeing as how we can't visualize objects in dimensions higher than 3d.
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    Fanatic Member alkatran's Avatar
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    Of course not (I knew someone would say that). But we can 'put' 3d objects on 2d surfaces, so we could put a 4d object on a 3d surface (and then on a 2d) to get .. a general idea, right?
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    Originally posted by alkatran
    Of course not (I knew someone would say that). But we can 'put' 3d objects on 2d surfaces, so we could put a 4d object on a 3d surface (and then on a 2d) to get .. a general idea, right?
    well, go ahead and 'put' it on a 3d object, but i doubt it would make sense. when you represent a 3d object on a 2d object, it is only possible because we are capable of understanding what it looks like in 3d (because we've seen it before). or at least that's what i think.
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    Frenzied Member Acidic's Avatar
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    Last edited by Acidic; Apr 12th, 2004 at 02:46 PM.
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    Only Slightly Obsessive jemidiah's Avatar
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    Probably the easiest way would be to lock 1 dimension of the cube and simply represent it as a 3d object. You could make a movie (adding one more dimension, time) that would accurately show a hypercube. Time would corrolate to the 4th dimension of the cube, causing it to be a represenation of a four-d object (only because we actually have 4 dimensions )
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    Fanatic Member alkatran's Avatar
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    After reading that... wow.. A lot of it is just too hard to imagine. I liked the pics of the hypercube though.
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