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Thread: quadratic formula derived

  1. #1

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    Hyperactive Member Sneeden's Avatar
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    quadratic formula derived

    A co workier of mine was asking about how this formaula was come up with. I could work it backwards to the Ax^2 + Bx + c =0, but when trying to go the other way, I could not explain where the number 4 comes from? Is it from "completeing the square"? or what?

  2. #2
    Frenzied Member nishantp's Avatar
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    I learnt this in grade 10. Its just a bunch of transformations. I'll dig it up and post it later.
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  3. #3
    Frenzied Member nishantp's Avatar
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    As it turns out, my grade 10 math teacher wasnt the only one who knew.

    http://mathforum.org/library/drmath/view/53153.html

    and here http://library.thinkquest.org/29292/...lving/3derive/
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    ax2 + bx + c = 0

    x2 + bx/a + c/a = 0

    x2 + bx/a = -c/a

    x2 + bx/a + b2/4a2 = b2/4a2 - c/a

    Bolded term makes left side a perfect square.

    (x + b/2a)2 = b2/4a2 - 4ac/4a2

    x + b/2a = SquareRoot( b2/4a2 - 4ac/4a2 )

    x + b/2a = SquareRoot( b2 - 4ac)/2a

    x = -b/2a + SquareRoot( b2 - 4ac)/2a

    The above is close enough to the standard formula.
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  5. #5
    Frenzied Member nishantp's Avatar
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    You may want to mention that the b2/4a2 comes from completing the square.
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