return{Resolved}

[quipy]

public int woo(int a){

int y = 78;

for(int i=0; i<100; i+10){ //i+10 is invalid
if (i == a)
return y;
}

return a;

}

I want the method to return 'y' if 'a' == 'i'.

if i == a, will the for loop be stopped (no further loops) and y be returned (ending the method)?
therefore, if i != a, a will be returned?

by the way, how do i get the increment of i to be +10 in every pass?

[Dillinger4]

public class X{
  public static void main(String[] args){

  for(int i = 0; i <=100; i += 10)  {
    System.out.println(i);
 }
}

[Dillinger4]

 public class X{
   public static void main(String[] args){

    int result = woo(52);
    System.out.println(result);
 
 }

  public static int woo(int a){

    boolean match = false;    

    for(int i = 0; i <=100; i += 10){
      if(i == a){
       match  = true;
       break;
     }
    }
    
    int result = match ?  78 : a;
    return result;
  }
}