Need help with factoring.

[Dillinger4]

Im not quite sure if this is how this is commonly solved. Any help would be great.

I have to factor. y(y+6 ) - 3(y + 6) which ends up (y +6)(y-3).

Would this be the correct way to factor?

y² + 6y - 3y - 18
y² + 3y - 18

Now since y * y = y² I put (y (y and since the L in FOIL has to equal -18 i end up with (y + 6)(y-3) bucause 6 * -3 = 18.

[DiGiTaIErRoR]

You did it correctly.

[Dillinger4]

Thanks for the help.

[sql_lall]

yeah, thats right.

in general, if you have:

y² + ay + b

and you want to factorise to:

(y+g)(y+h)

then you just need to find the two numbers such that:
g+h = a
gh = b

i.e. their sum is a, and their product is b.

[Guv]

Looks like more work than necessary.

I have to factor. y(y+6 ) - 3(y + 6) which ends up (y +6)(y-3).

Suppose you were asked to factor: y*x - 3*x?

Wouldn't you immediately reply: (y - 3) *x ?

Think of (y + 6) as x.