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Thread: SSN Algorithm

  1. #1
    Guest
    Wondering if there is an algorithm out there that will tell you if a SSN is valid? I am writing a front-end to a user database and am having problems with false SSNs being entered for employees if the data entry person doesn't have it in front of them.



    [Edited by tredfoot on 09-14-2000 at 05:34 PM]

  2. #2
    Frenzied Member
    Join Date
    Jul 1999
    Location
    Huntingdon Valley, PA 19006
    Posts
    1,151

    I do not think so.

    If the Social security Administration cannot help you, I do not think there is an algorithm.

    I doubt that they will help. I suspect that the only way to validate is to have a database with all the numbers in it.

    If you are working somewhere requiring W2 forms, Payroll withholding, et cetera, perhaps IRS or SSA would would verify on request or automatically when first government forms must be filed.
    Live long & prosper.

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  3. #3
    Addicted Member
    Join Date
    Oct 2000
    Location
    Orlando, FL
    Posts
    253

    Lightbulb SSN Varify Method

    Hey, I use a varify code for my program to varify the SSN for a text box. You can specify the use of a seperator with this code as well. For Example: 999-99-9999 or 999999999. There are only 3 parts to this code and is not complicated. Here is the code:
    Code:
    Private Function SSNValidate(strSSN As String, _
        Optional bolSeperator As Boolean) As String
    Dim bolNotValid As Boolean
    Dim intSeperator As Integer
    Dim intLength As Integer
    Dim strSeperator As String
    
    'Determines the length the SSN should be.
    If bolSeperator Then
        intLength = 11
        intSeperator = 1
        strSeperator = "-"
    Else 'Seperator specified
        intLength = 9
    End If
    
    'Starts by checking the length of the value
    If Len(strSSN) = intLength Then
        'If the length is valid then it checks for valid
        'characters inside the value
        If IsNumeric(Left(strSSN, 3)) And _
            IsNumeric(Mid(strSSN, 5, 2)) And _
            IsNumeric(Right(strSSN, 4)) And _
            Mid(strSSN, 4, intSeperator) = strSeperator And _
            Mid(strSSN, 7, intSeperator) = strSeperator Then
            SSNValidate = strSSN 'Stores value
        Else
            bolNotValid = True
        End If
        
    Else
        bolNotValid = True
    End If
    
    'If the value is not correct a message is displayed and
    'the return value is an empty string
    If bolNotValid Then
        MsgBox "The social security number is not valid.  " & _
            "If you don't specify a correct value, " & _
            "the value will be deleted the next time this " & _
            "record is updated.", vbInformation, "Invalid SSN"
        SSNValidate = "   -  -    " 'Return empty string for a
                                    'masked edit control.
    End If
    End Function
    If you find a more efficient way, please let me know. I hope this helps you out.

  4. #4
    Guest
    I don't think you can in the sense of making sure you have
    a valid SSN. MIBEN's function will guarrantee that you
    have the right pattern.

    I KNOW that the last three digits are assigned sequentially
    (as a matter of fact, you can use them to perform a random
    selection from the SSN.......).

    I have been told that the first 3 and middle 2 digits mean
    something. Something about where in the country it was
    issued, but I don't know what it is.


    Good Luck
    DerFarm

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