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Thread: Quick math help

  1. #1

    Thread Starter
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    Quick math help

    Im usually pretty good at these types of problems but this one seems to puzzle me. x(x-y)-y(y-x)-(x2-y2)
    What i end up getting boils down to -xy + yx Thanks

  2. #2
    Fanatic Member sql_lall's Avatar
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    Talking =0

    multiplication of numbers works either way (there is a word for this, i just can't remember it right now)
    => -xy + yx
    = xy-xy = 0 (which i hope is the required answer)

    However, if x and y are matrices, i'm not sure how this would be done.

    To check:
    x(x-y)-y(y-x) = x(x-y)+y(x-y) = (x+y)(x-y) = x2-y2

    x2-y2 - (x2-y2) = 0
    sql_lall

  3. #3

    Thread Starter
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    Humm very interesting. I kinda thought that zero might be the solution but i wasn't too sure. I guess if values are substituted then the answer becomes apparent. -1(3) + 3(1) = 0 Thanks for the help.

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