|
-
Feb 11th, 2003, 03:31 AM
#1
Speed problem with current(Resolved)
Hi I'm trying to solve this problem, but I can'T get the solution exempt by try and error. What am I doing wrong?
Problem:
A ship travels along a river from A to B and back. Time required for both ways is 11,5 hrs. The river has a current of 2,5 Knots(Nm/hr). The distance from A to B is 91 Nm.
What's the speed of the ship (speed thru water!)
I have:
T1= Time to travel from A to B (with the current)
T2= Time to travel from B to A (against the current)
V= Speed of Ship (Speed thru the water)
T2=11,5 hrs -T1
The equation is:
2*91= T1*(V+2,5) + (11,5-T1)*(V-2,5)
I can convert this one back and for, but T1 and V will allways be in there. How would I get the correct value for V?
Note 15,8 is not the coorect one, this one would assume no current and T1=T2!
By try and error I got 16,2 Kn
Last edited by opus; Feb 11th, 2003 at 04:53 AM.
You're welcome to rate this post!
If your problem is solved, please use the Mark thread as resolved button
Wait, I'm too old to hurry!
-
Feb 11th, 2003, 03:52 AM
#2
T1 + T2 = T = 11.5 h
Vr = 2.5 Nm/h
d(A-B) = 91 Nm
Time for A to B travel: T1 = d / (V + Vr)
Time for B to A travel: T2 = d / (V - Vr)
Add these 2 up:
T = d[1/(V + Vr) + 1/(V - Vr)]
The rest is easy and you come up with a second degree equation:
V2 - (2d/T)V - Vr2 = 0
Solving for V you get 16.212 Nm/h
Last edited by krtxmrtz; Feb 11th, 2003 at 05:09 AM.
-
Feb 11th, 2003, 04:53 AM
#3
Thank's, so the problem was not to start with TotalTime.
You're welcome to rate this post!
If your problem is solved, please use the Mark thread as resolved button
Wait, I'm too old to hurry!
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|