Initialising arrays of objects

[Barguast]

Me again.

When you create an array of objects, how can you pass the arguments required by the constructor?

example:

when you declare a single object it might look something like this:

clsComplex Number(2,1);

but when you declare an array of objects:

clsComplex Number[3];

How do you also add the arguments for the constructors?

[MikeyD]

You cannot do it that way.

You have to allocate You objects at run-time (on heap) through new:

clsComplex* ppComplex[3];
for (int x=0; x < 3;++x)
{
	ppComplex[x] = new clsComplex(2,1); // call ctor with arguments
}

Don't forget to delete Your array-ptrs. after use!

Mikey

[parksie]

I don't know, it should be possible:

object blah[3] = { object(4,5), object(2, 89), object(69, 31337) };

[Barguast]

Both work. Thanks muchly

[parksie]

Note that the first is more flexible, while the second is more efficient (and you don't need to delete afterwards).

[Barguast]

Just as an addition, since it's kind of related:

What's up with this:

BYTE bArray[5];

bArray={1,2,3,4,5};

I can't use this "BYTE bArray[5]={1,2,3,4,5};" because the array values will changes.

Just to be specific, the code should assign 1 to bArray[0], 2 to bArray[1] etc.

[parksie]

You can use the second one, since you can still change the array contents.

It's only impossible to change it if you declare the array as const.

[MikeyD]

parksie is right,
You only need the new-op. if You have to decide at runtime, how large Your array is
or if You have to change the array-size.

Mikey

[Barguast]

errr, how?

(I know I'm a pain)

[MikeyD]

what You mean - "how"?

[MikeyD]

if You mean with "how", how to assign new values to Your array:

BYTE bArray[5] = {1,2,3,4,5};

bArray[3] = 6; // assign a new value to index 3

[Barguast]

I was replying to parksie's , sorry

I wanted to know how I could change the contents of the array using the method you both describe.