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Thread: Determine the smallest k for all +ve n!

  1. #1

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    Determine the smallest k for all +ve n!

    Determine the smallest integer k such that is divisible by 1441 for all positive integers n.
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    YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)

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    Hey, you're stealing all the problems from Dr White's math sheets!!!
    Merry Math Making!

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    Fanatic Member bugzpodder's Avatar
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    hmm can you do it KalKewl8ter? this one proves to be somewhat of a challenge. also u know that Dr. White 'stole' these problems from Euclid and Decartes contest?
    Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!


    Did you know that...
    The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!

  4. #4
    Fanatic Member bugzpodder's Avatar
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    I hate you SS! you give me a question that has no solution and expect me to find a solution! I proved that in 5 minutes but apparently i wasn't 'confident enough' in my answers and kept searching for an answer for the next 1 and half hour with of course no luck, even using programming!!!
    Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!


    Did you know that...
    The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!

  5. #5
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    I agree with bugz, although I was almost positive that I had seen someone come up with a solution that led to an answer before...?
    Merry Math Making!

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    Fanatic Member bugzpodder's Avatar
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    i better provide a solution to back me up:

    apparently if a+bz=cz (Rule X)
    a=z(c-b)
    then a must be divisible by z, if a,b,c,z are integers

    all letters below are [positive] integers

    60n+k*71n=1441x

    60n+1+k*71n+1=1441y

    ok second equation can be written as:

    60*60n+71*k*71n=1441y

    60*60n+60*k*71n+11*k*71n=1441y

    60(60n+k*71n)+11*k*71n=1441y

    60(1441x)+11*k*71n=1441y

    By rule X,

    11*k*71n=1441y' (where y' is also an integer)

    k*71n=131y'

    apparently since 131 is not divisible by 71, k must be divisible by 131

    and we have:

    60n+k*71n=1441x

    when n=1

    60+71k=1441x

    60+71*(131y')=131*11*x

    by Rule X,

    60 has to be divisible by 131 which apparently is not, therefore no solution
    Last edited by bugzpodder; Sep 13th, 2002 at 10:49 PM.
    Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!


    Did you know that...
    The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!

  7. #7

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    Kalkewl8ter, I dont know WHAT your talking about!
    YL says:"Few are those who see with their own eyes and feel with their own hearts."(Einstein)

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