hmm can you do it KalKewl8ter? this one proves to be somewhat of a challenge. also u know that Dr. White 'stole' these problems from Euclid and Decartes contest?
Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
I hate you SS! you give me a question that has no solution and expect me to find a solution! I proved that in 5 minutes but apparently i wasn't 'confident enough' in my answers and kept searching for an answer for the next 1 and half hour with of course no luck, even using programming!!!
Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!
apparently if a+bz=cz (Rule X)
a=z(c-b)
then a must be divisible by z, if a,b,c,z are integers
all letters below are [positive] integers
60n+k*71n=1441x
60n+1+k*71n+1=1441y
ok second equation can be written as:
60*60n+71*k*71n=1441y
60*60n+60*k*71n+11*k*71n=1441y
60(60n+k*71n)+11*k*71n=1441y
60(1441x)+11*k*71n=1441y
By rule X,
11*k*71n=1441y' (where y' is also an integer)
k*71n=131y'
apparently since 131 is not divisible by 71, k must be divisible by 131
and we have:
60n+k*71n=1441x
when n=1
60+71k=1441x
60+71*(131y')=131*11*x
by Rule X,
60 has to be divisible by 131 which apparently is not, therefore no solution
Last edited by bugzpodder; Sep 13th, 2002 at 10:49 PM.
Massey RuleZ! ^-^__Cheers!__^-^ Massey RuleZ!
Did you know that...
The probability that a random rational number has an even denominator is 1/3 (Salamin and Gosper 1972)? This result is independently verified by me (2002)!