consider the document:
Code:
[color="royal blue"]<xmldata>
  <xml some namespace data>
    <rs:data>
      <z:row cust_name="Bill" />
      <z:row cust_name="Frank" />
      <z:row cust_name="Joe" />
   </rs:data>
  </xml>
</xmldata>[/color]
I have a stylesheet using xsl that prints out my rows nicely. When I change it to xslt (because I want to use the position() function), the xpath statement used in my template match criteria no longer finds my rows. I believe this is due to the namspaces in the xml document. (like it can't find <rs:data>. but if the xml were different, it would find <data>. The xml's not going to change, and I'd rather not try to style it once before I style it again. any suggestions as to what to do?
Code:
[color="royal blue"]<xsl:stylesheet  version="1.0"
    xmlns:xsl="http://www.w3.org/TR/WD-xsl"
    >
<!-- This works, but I can't use the position() function with it. //-->
<!-- If I switch the xsl namespace URI to be XSLT 
(http://www.w3.org/1999/XSL/Transform),
it doesn't produce my rows anymore //-->

<xsl:template match="/">
  <TABLE>
    <TR>
      <TD>Customer Name</TD>
      <TD>Rank</TD>
    </TR>
    <xsl:apply-templates select="/xmldata/xml/rs:data/z:row" />
<!-- this is where the problem lies -->
  </TABLE>
</xsl:template>

<xsl:template match="/xmldata/xml/rs:data/z:row">
  <TR>
    <TD><xsl:value-of select="@cust_name" /></TD>
    <TD><xsl:value-of select="position()" /></TD>
  </TR>
</xsl:template>

</xsl:stylesheet>
[/color]