Filling an array with a string

[johnerr]

How would one go about putting the characters of a sting into the index of an array?
eg.
For i = 1 To 8
array(i) = "abcdefgh"
Next
I want array(1) to be a , array(2) to be b and so on.
Thanks

[jim mcnamara]

memset(arr,'\0',sizeof(arr));  // zero out the array
for (i=1;i<9;i++){
    arr[i-1] = i;  
}

The problem is: arrays start counting with zero, and zero is used by C to mark the end of a string so:

arr[0]=0;

will create an array with no length - like a null string in VB.
So,

arr[0]=' ';

or something like that for the first element

[jim mcnamara]

or this

char c;
int i=0;
for (c='a';c<='h';c++){
     arr[i++]=c;
}

my problem is I have no idea what you want....